#11
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A rod lies parallel to the x-axis of reference frame S, moving along this axis at a speed of 0.632 C. Its rest length is 1.68m. What will be its measured length in frame S?
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#12
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Three vectors are given by:
a = 3i + 3j -2k b = -i - 4j + 2k c = 2i + 2j – k Find (i) a. (b. × c), (ii) a. (b. + c), (iii) a. × (b + c) The problem is written as (b. × c) it must be either (b × c or b . c). Am i right? I have tried the first one through matrices and the simple cross method the answer is (b × c)= 3j + 6k or it is b . c thats why i am getting the wrong answer. Resolve issues. The second is find the value of e so that A = ci – 2j + k and B = 2ci + cj – 4k are perpendicular. Its not e its c. I solved it by dot product as ********* A . B = ABcos90°= 0 because A B are perpendicular. But didn,t get the answer.**** Regards. |
#13
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Quote:
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#14
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#15
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Quote:
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#16
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I solved it as ABcos90 and got the same answer after applying quadratic formula. There is some mistake in the problem, for we get two values not one.
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#17
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Quote:
Before formula, you should also mention "Using Lorentz–FitzGerald contraction, the length observed in relative motion with the object is,". These are just my views; you may disagree. |
#18
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If you are getting 2 answers then what is the confusion.Why you are thinking that there should be one answer. Both are correct and you can verify by putting the value of c and then taking the bot product.and your method is also correct if you are getting these 2 values.
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#19
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Agree. I'll mention it in the remaining problems. Do you possess past papers of 2003, 2004 and 2006. These are not opening on the forum.
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#20
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No .
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mechanics, past papers, physics, solutions |
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