I verified and get the answer 0. I was in confusion about using quadratic formula in the vector portion.
|
To which part the problem show that Vr=r^n-2 r belong. I have not studied it.:thinking
Prove that thenecessary and sufficient condition for A B and C to be coplanar is A . B × C = 0 [IMG]http://s24.postimg.org/ognxejkxx/20150525_152837.jpg[/IMG] |
[QUOTE=AZKAFATIMA;832367]To which part the problem show that Vr=r^n-2 r belong. I have not studied it.:thinking
[/QUOTE] Here is the solution. I have skipped many steps, just to compel you to do it yourself. Lol It will make your concept clear. [IMG]http://i.imgur.com/dFYnb4g.jpg[/IMG] |
I have solved it as.
[IMG]http://s2.postimg.org/pzso4717t/20150525_190310.jpg[/IMG] |
Sketch the function V = -yx+xy
[IMG]http://s16.postimg.org/79oo5s9jp/20150526_183025.jpg[/IMG] Share the method if V is the scalar field |
Can anybody elucidate divergence and curl. I studied but didn't get even a single notation.:cry
Should i go for video lectures as i am preparing myself. |
[QUOTE=IslamabadKid;831787]Yes, it is "j+k."
Here is the solution: [IMG]http://i.imgur.com/NDUYSnG.jpg[/IMG] Redo this again, as I have just done it hurriedly. I hope it is correct; however, if you find any error, do mention it. :) NOTE: I shall share another method as well, which involves matrices. That method seems more elegant to me than the aforementioned one.[/QUOTE] Isn't the magnitude at the end wrong? Shouldn't it be "Underroot 3?" |
Mechanics queries
[QUOTE=Noore776;836809]Can anybody elucidate divergence and curl. I studied but didn't get even a single notation.:cry
Should i go for video lectures as i am preparing myself.[/QUOTE] I shall explain you both this morning[B] in detail.[/B] (2:59 AM right now lol) [QUOTE=Norymberskie;836852]Isn't the magnitude at the end wrong? Shouldn't it be "Underroot 3?"[/QUOTE] The magnitude is underroot 3! I left last step of finding unit vector, which has to be: Given vector - i-j+k - over its magnitude, for the member who asked this question. AxB gives you a perpendicular vector, not perpendicular *unit* vector. (1) doubletick at the end means you have everything now at your disposal to find the perpendicular unit(1) vector. Hope this makes it clear! |
[QUOTE=Noore776;836809]
Should i go for video lectures because i am preparing myself.[/QUOTE] Video lectures is a good option but in this option we cannot ask any questions. You must seek guidance from the forum and if you belong to an educated family, you must take help from an engineer. Unfortunately, i have no engineer in my family. |
Yes, i can avail this option. A brother in my family is studying civil engineering. Thanks for suggestion.
|
05:35 AM (GMT +5) |
vBulletin, Copyright ©2000 - 2024, Jelsoft Enterprises Ltd.