[B]another question.........

y dipole moment and quardopole moment not exsist in nucleus?[/B]

[QUOTE=mitariq;230957][B]Conservation of strangeness:[/B]
a product of a proton collision with a nucleus was found to live for much longer time than expected: 10^-10 seconds instead of the expected 10^-23 seconds! This particle was named the lambda particle and the property which caused it to live so long was dubbed "strangeness" and that name stuck to be the name of one of the quarks(Quarks and Leptons are the building blocks which build up matter, i.e., they are seen as the "elementary particles".) from which the lambda particle is constructed. The lambda is a baryon(Proton,Neutron,Lambda,Sigma,Delta etc) which is made up of three quarks: an up, a down and a strange quark.

The shorter lifetime of 10-23 seconds was expected because the lambda as a baryon participates in the strong interaction, and that usually leads to such very short lifetimes. The long observed lifetime helped develop a new conservation law for such decays called the "conservation of strangeness". The presence of a strange quark in a particle is denoted by a quantum number S=-1.
Conservation of strangeness is not in fact an independent conservation law, but can be viewed as a combination of the conservation of charge, isospin, and baryon number. It is often expressed in terms of hypercharge Y, defined by:
Y=S+B=2(Q-I)
S=strangeness
B=Baryon number
Q=Electric charge
I=Isospin

[B]Conservation of charmness:[/B]
The Psi meson is composed of a new quark c(for charm)and its antiquark C prim. The c quark has an electric charge of +2/3. just as the strange quark is assigned a strangeness quantum number of S=-1, the charmed quark is assigned a charm of C=+1. The decay of the Psi meson is slowed, because the c quark must decay into other quark [COLOR="Blue"][U](u,d, or s)[/U][/COLOR], all which have C=0. the decay thus involves a violation of the conservation of charm and therefore can’t occur through the strong interaction , which conserves the law….
u=up
d=down
s=strange[/QUOTE]


[B]these laws also known as
"conservation of baryon and conservation of lepton"????[/B]

[QUOTE]conservation of baryon and conservation of lepton[/QUOTE]
no they are not,

hmmmmmm
n y dipole moment and quardropole moment is not conserved in nusleus?

[QUOTE]y dipole moment and Quadrupole moment not exsist in nucleus?[/QUOTE]
they do exist in the nucleus, both of them....
Quadrupole describe the shape of the nucleus.
[QUOTE]y dipole moment and quardropole moment is not conserved in nusleus?[/QUOTE]
there is no such law which defines the conservation of dipoles.

[QUOTE]they do exist in the nucleus, both of them....
Quadrupole describe the shape of the nucleus[/QUOTE]

kindly explain the exsistance of quadrupole and dipole in nucleus.......... what is its importance ?

One of the most common uses of the electric quadrupole is in the characterization of nuclei. The nucleus has charge, but not dipole moment since it is all positive. But if the nucleus is not spherically symmetric, it will have a quadrupole moment.

Quadrupole and higher order multipoles are not important for the characteriztion of dielectric materials. Dipole fields are much smaller than the fields of isolated charges, but in dielectrics where there are no free charges, the dipole effects are dominant. There is no such circumstance favoring the quadrupole effects, since they must arise from the same number of molecules as the dipole effects. Scott says that the macroscopic quadrupole effects are smaller than dipole effects by about the ratio of atomic dimensions to the distances of experimental observation.