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  #1  
Old Sunday, March 10, 2013
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Default marks for working?

I want to know does anyone have any idea if the examiner gives marks for working? i mean if the question says to solve it without replacement, and the person has overlooked that part, and the remaining procedure is same, except that there are two three different steps, will they give marks for working? If the question is of 10 marks, approximately how many will be given?
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  #2  
Old Wednesday, March 13, 2013
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Originally Posted by raindrop View Post
I want to know does anyone have any idea if the examiner gives marks for working? i mean if the question says to solve it without replacement, and the person has overlooked that part, and the remaining procedure is same, except that there are two three different steps, will they give marks for working? If the question is of 10 marks, approximately how many will be given?
It totally depends on examiner but i guess statistics is not a subject in which solving procedure can be squeezed. u will have to go step by step to get ultimate solved answer of an asked question. u gave example of sampling without replacement. there is a particular procedure of sampling without replacement which can't be minimized but if u go to another approach to solve the same question then it will be other case which will require to go thorough the whole step wise procedure of its own. u can choose the short method but u can't squeeze a particular procedure of solving a question.
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Old Saturday, March 16, 2013
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what i meant was that we had to draw the possible samples of 5 different elements. sample size was two. If sampling without replacement was done, then there were 10 samples but if with replacement, then 25. So what i did was, i accidently mixed up the two and drew 16 samples. these 16 include the 10 of the without replacement as well. So basically, the table shows 10 of without replacement, and then 6 additional. Will i get partial credit for this?
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  #4  
Old Saturday, March 16, 2013
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Quote:
Originally Posted by raindrop View Post
what i meant was that we had to draw the possible samples of 5 different elements. sample size was two. If sampling without replacement was done, then there were 10 samples but if with replacement, then 25. So what i did was, i accidently mixed up the two and drew 16 samples. these 16 include the 10 of the without replacement as well. So basically, the table shows 10 of without replacement, and then 6 additional. Will i get partial credit for this?
I don't think you would be given any credit. As the base of your estimation is wrongfully built. Rest Allah and examiner knows best.
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Old Saturday, March 16, 2013
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Quote:
Originally Posted by raindrop View Post
what i meant was that we had to draw the possible samples of 5 different elements. sample size was two. If sampling without replacement was done, then there were 10 samples but if with replacement, then 25. So what i did was, i accidently mixed up the two and drew 16 samples. these 16 include the 10 of the without replacement as well. So basically, the table shows 10 of without replacement, and then 6 additional. Will i get partial credit for this?
You will deserve no mark(s) for this Question. Your approach was totally wrong as you didn't follow the true procedure for this question.
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