CSS Forums

CSS Forums (http://www.cssforum.com.pk/)
-   CSS 2016 Papers (http://www.cssforum.com.pk/css-past-papers/css-papers-1971-2017/css-2016-papers/)
-   -   General Science & Ability Paper 2016 (http://www.cssforum.com.pk/css-past-papers/css-papers-1971-2017/css-2016-papers/107703-general-science-ability-paper-2016-a.html)

hammadtahir Saturday, January 28, 2017 11:21 AM

Complete Solution of 12(a)
 
[B][I]Data:[/I][/B]
Total Events/Sample Space/No. of People = 1000
People having Blood Group A = 300
People having Blood Group B = 325
People having Blood Group O = 250
People having Blood Group AB = 125

[B][I]Solution:[/I][/B]
Probability of having Blood Group AB = People having Blood Group AB / Total Number of People

Probability of having Blood Group AB = 125/1000
Probability of having Blood Group AB = [B][I]0.125[/I][/B]

hammadtahir Saturday, January 28, 2017 12:09 PM

Complete Solution of 12(b)
 
[B][I]Data:[/I][/B]
Persons = 5
Ahmad, Ali, Akbar, Nasir and Shehbaz

Cities = 5
V, W, X, Y and Z

Modes of Transport = 5
Bus, Train, Aeroplane, Car and Boat

[B][I]Scenario:[/I][/B]

[B][I]Person Mode of Transport City[/I][/B]
Akbar Car Y
Ali Aeroplane X
Nasir Boat
Shehbaz Train

Bus ≠ X, W
Boat ≠ X

So,
The remaining mode of transport is now Bus
and the remaining person is Ahmad
so, Ahmad must traveled by Bus
and
Remaining Cities are X, W and Z

Therefore,
[B][I]Person Mode of Transport City[/I][/B]
Akbar Car Y
Ali Aeroplane X
Nasir Boat
Shehbaz Train
Ahmad Bus

As there is no Bus Service towards X and W.
So, there is two possibilities which are:

[B][I]#1
Person Mode of Transport City[/I][/B]
Akbar Car Y
Ali Aeroplane X
Nasir Boat W
Shehbaz Train
Ahmad Bus

[B][I]#2
Person Mode of Transport City[/I][/B]
Akbar Car Y
Ali Aeroplane X
Nasir Boat
Shehbaz Train W
Ahmad Bus

So, Now There is two further possibilities of each case (#1 and #2) having total of 4 possibilities or scenario

[B][I]#1
[Possibility 1]
Person Mode of Transport City[/I][/B]
Akbar Car Y
Ali Aeroplane X
Nasir Boat W
Shehbaz Train V
Ahmad Bus Z

[B][I]#1
[Possibility 2]
Person Mode of Transport City[/I][/B]
Akbar Car Y
Ali Aeroplane X
Nasir Boat W
Shehbaz Train Z
Ahmad Bus V

[B][I]#2
[Possibility 3]
Person Mode of Transport City[/I][/B]
Akbar Car Y
Ali Aeroplane X
Nasir Boat V
Shehbaz Train W
Ahmad Bus Z

[B][I]#2
[Possibility 4]
Person Mode of Transport City[/I][/B]
Akbar Car Y
Ali Aeroplane X
Nasir Boat Z
Shehbaz Train W
Ahmad Bus V

[B][I]Questions:[/I][/B]
[I][B]i. How did Ahmed travel and where did he go?[/B][/I]
So, by viewing these 4 Possibilities
Ahmed must traveled through [B][I]Bus[/I][/B] to either go to the City [B][I]V or Z[/I][/B].

[B][I]ii. Which mode of transport was used by the person who traveled to X city?[/I][/B]
In every possibility
Ali traveled through [I][B]Aeroplane[/B][/I] to reach the city X.

hammadtahir Saturday, January 28, 2017 12:29 PM

Complete Solution of 12(b)
 
Data:
Persons = 5
Ahmad, Ali, Akbar, Nasir and Shehbaz

Cities = 5
V, W, X, Y and Z

Modes of Transport = 5
Bus, Train, Aeroplane, Car and Boat

[B][I]Scenario:

Person : Mode of Transport : City[/I][/B]
Akbar : Car : Y
Ali : Aeroplane : X
Nasir : Boat :
Shehbaz : Train :

Bus ≠ X, W
Boat ≠ X

So,
The remaining mode of transport is now Bus
and the remaining person is Ahmad
so, Ahmad must traveled by Bus
and
Remaining Cities are X, W and Z

Therefore,
[B][I]Person : Mode of Transport : City[/I][/B]
Akbar : Car : Y
Ali : Aeroplane : X
Nasir : Boat :
Shehbaz : Train :
Ahmad : Bus :

As there is no Bus Service towards X and W.
So, there is two possibilities which are:

[B][I]#1
Person : Mode of Transport : City[/I][/B]
Akbar : Car : Y
Ali : Aeroplane : X
Nasir : Boat : W
Shehbaz : Train :
Ahmad : Bus :

[B][I]#2
Person : Mode of Transport : City[/I][/B]
Akbar : Car : Y
Ali : Aeroplane : X
Nasir : Boat :
Shehbaz : Train : W
Ahmad : Bus :

So, Now There is two further possibilities of each case (#1 and #2) having total of 4 possibilities or scenario

[B][I]#1
[Possibility 1]
Person : Mode of Transport : City[/I][/B]
Akbar : Car : Y
Ali : Aeroplane : X
Nasir : Boat : W
Shehbaz : Train : V
Ahmad : Bus : Z

[B][I]#1
[Possibility 2]
Person : Mode of Transport : City[/I][/B]
Akbar : Car : Y
Ali : Aeroplane : X
Nasir : Boat : W
Shehbaz : Train : Z
Ahmad : Bus : V

[B][I]#2
[Possibility 3]
Person : Mode of Transport : City[/I][/B]
Akbar : Car : Y
Ali : Aeroplane : X
Nasir : Boat : V
Shehbaz : Train : W
Ahmad : Bus : Z

[B][I]#2
[Possibility 4]
Person : Mode of Transport : City[/I][/B]
Akbar : Car : Y
Ali : Aeroplane : X
Nasir : Boat : Z
Shehbaz : Train : W
Ahmad : Bus : V

[B][I]Questions:
i. How did Ahmed travel and where did he go?[/I][/B]
So, by viewing these 4 Possibilities
Ahmed must traveled through Bus to either go to the City V or Z.

[B][I]ii. Which mode of transport was used by the person who traveled to X city?[/I][/B]
In every possibility
Ali traveled through Aeroplane to reach the city X.

hammadtahir Saturday, January 28, 2017 12:44 PM

Complete Solution of 11(a)
 
[B][I](i) How many stores does the distribution company serve?[/I][/B]
Total Number of stores = 3+15+26+20+16=[B][I]80[/I][/B]

[B][I](ii) What is the most common distance of stores from the company's godown?[/I][/B]
For this always see maximum frequency which is 26 in this table/case:
So,
The most common distance of stores from the company's godown is [B][I]21 to 30 kilometers[/I][/B] (because it has the maximum frequency; 26 stores).

[B][I](iii) How many stores are 35 km or more from the godown?[/I][/B]
From Table:
There are [B][I]16 stores[/I][/B] which are [B][I]41 km or more from the godown[/I][/B], and [B][I]20 stores[/I][/B] which are between [B][I]31 to 40 km from the godown[/I][/B]. From the table we cannot say anything that how many of these 20 stores are 35 km or more from the godown.

[B][I](iv) What percentage of stores are 31 km or more from the godown?[/I][/B]
There are 20+16=36 stores which are 31 km or more from the godown. Hence, the percentage of these stores is given as,
36/Total no. of stores = 36/80 = 0.45
0.45 x 100%
[B][I]45%[/I][/B]

hammadtahir Saturday, January 28, 2017 12:58 PM

Complete Solution of 10(b)
 
[B][I]Data:[/I][/B]
15, 15, 16, 16, 16, 17, 17, 18, 19

[B][I]Solution:[/I][/B]
The mean is defined as, the sum of the values divided by the number of values.
The mean of the above data set is given as,
=15+15+16+16+16+17+17+18+19/9
=149/9
=[B][I]16.556[/I][/B]

[B][I]Median:[/I][/B]
The middle value of an arranged data set is called median.
Arranged data means writing the values in ascending order. The given values in ascending order are given as:
15, 15, 16, 16, 16, 17, 17, 18, 19 (already in ascending order)
Hence, the median of the above data set is given as
[U]15+15+16+16[/U]+16+[U]17+17+18+19[/U]
Median = [B][I]16[/I][/B]

[B][I]Mode:[/I][/B]
The mode is the most repeated value in a data set.
The most repeated value in the given data is 16.
So, Mode = [B][I]16[/I][/B]

[B][I]Range:[/I][/B]
Range is the difference between the largest value and the smallest value.
In the given data set the largest value is 19, and the smallest value is 15. Hence,
Range = 19 − 15 = [B][I]4[/I][/B]

Sumaira7777 Monday, January 28, 2019 11:01 AM

Is that removed? Paper isn't visible now

Sent from my LDN-L21 using Tapatalk


01:24 AM (GMT +5)

vBulletin, Copyright ©2000 - 2024, Jelsoft Enterprises Ltd.