Complete Solution of 12(a)
[B][I]Data:[/I][/B]
Total Events/Sample Space/No. of People = 1000 People having Blood Group A = 300 People having Blood Group B = 325 People having Blood Group O = 250 People having Blood Group AB = 125 [B][I]Solution:[/I][/B] Probability of having Blood Group AB = People having Blood Group AB / Total Number of People Probability of having Blood Group AB = 125/1000 Probability of having Blood Group AB = [B][I]0.125[/I][/B] |
Complete Solution of 12(b)
[B][I]Data:[/I][/B]
Persons = 5 Ahmad, Ali, Akbar, Nasir and Shehbaz Cities = 5 V, W, X, Y and Z Modes of Transport = 5 Bus, Train, Aeroplane, Car and Boat [B][I]Scenario:[/I][/B] [B][I]Person Mode of Transport City[/I][/B] Akbar Car Y Ali Aeroplane X Nasir Boat Shehbaz Train Bus ≠ X, W Boat ≠ X So, The remaining mode of transport is now Bus and the remaining person is Ahmad so, Ahmad must traveled by Bus and Remaining Cities are X, W and Z Therefore, [B][I]Person Mode of Transport City[/I][/B] Akbar Car Y Ali Aeroplane X Nasir Boat Shehbaz Train Ahmad Bus As there is no Bus Service towards X and W. So, there is two possibilities which are: [B][I]#1 Person Mode of Transport City[/I][/B] Akbar Car Y Ali Aeroplane X Nasir Boat W Shehbaz Train Ahmad Bus [B][I]#2 Person Mode of Transport City[/I][/B] Akbar Car Y Ali Aeroplane X Nasir Boat Shehbaz Train W Ahmad Bus So, Now There is two further possibilities of each case (#1 and #2) having total of 4 possibilities or scenario [B][I]#1 [Possibility 1] Person Mode of Transport City[/I][/B] Akbar Car Y Ali Aeroplane X Nasir Boat W Shehbaz Train V Ahmad Bus Z [B][I]#1 [Possibility 2] Person Mode of Transport City[/I][/B] Akbar Car Y Ali Aeroplane X Nasir Boat W Shehbaz Train Z Ahmad Bus V [B][I]#2 [Possibility 3] Person Mode of Transport City[/I][/B] Akbar Car Y Ali Aeroplane X Nasir Boat V Shehbaz Train W Ahmad Bus Z [B][I]#2 [Possibility 4] Person Mode of Transport City[/I][/B] Akbar Car Y Ali Aeroplane X Nasir Boat Z Shehbaz Train W Ahmad Bus V [B][I]Questions:[/I][/B] [I][B]i. How did Ahmed travel and where did he go?[/B][/I] So, by viewing these 4 Possibilities Ahmed must traveled through [B][I]Bus[/I][/B] to either go to the City [B][I]V or Z[/I][/B]. [B][I]ii. Which mode of transport was used by the person who traveled to X city?[/I][/B] In every possibility Ali traveled through [I][B]Aeroplane[/B][/I] to reach the city X. |
Complete Solution of 12(b)
Data:
Persons = 5 Ahmad, Ali, Akbar, Nasir and Shehbaz Cities = 5 V, W, X, Y and Z Modes of Transport = 5 Bus, Train, Aeroplane, Car and Boat [B][I]Scenario: Person : Mode of Transport : City[/I][/B] Akbar : Car : Y Ali : Aeroplane : X Nasir : Boat : Shehbaz : Train : Bus ≠ X, W Boat ≠ X So, The remaining mode of transport is now Bus and the remaining person is Ahmad so, Ahmad must traveled by Bus and Remaining Cities are X, W and Z Therefore, [B][I]Person : Mode of Transport : City[/I][/B] Akbar : Car : Y Ali : Aeroplane : X Nasir : Boat : Shehbaz : Train : Ahmad : Bus : As there is no Bus Service towards X and W. So, there is two possibilities which are: [B][I]#1 Person : Mode of Transport : City[/I][/B] Akbar : Car : Y Ali : Aeroplane : X Nasir : Boat : W Shehbaz : Train : Ahmad : Bus : [B][I]#2 Person : Mode of Transport : City[/I][/B] Akbar : Car : Y Ali : Aeroplane : X Nasir : Boat : Shehbaz : Train : W Ahmad : Bus : So, Now There is two further possibilities of each case (#1 and #2) having total of 4 possibilities or scenario [B][I]#1 [Possibility 1] Person : Mode of Transport : City[/I][/B] Akbar : Car : Y Ali : Aeroplane : X Nasir : Boat : W Shehbaz : Train : V Ahmad : Bus : Z [B][I]#1 [Possibility 2] Person : Mode of Transport : City[/I][/B] Akbar : Car : Y Ali : Aeroplane : X Nasir : Boat : W Shehbaz : Train : Z Ahmad : Bus : V [B][I]#2 [Possibility 3] Person : Mode of Transport : City[/I][/B] Akbar : Car : Y Ali : Aeroplane : X Nasir : Boat : V Shehbaz : Train : W Ahmad : Bus : Z [B][I]#2 [Possibility 4] Person : Mode of Transport : City[/I][/B] Akbar : Car : Y Ali : Aeroplane : X Nasir : Boat : Z Shehbaz : Train : W Ahmad : Bus : V [B][I]Questions: i. How did Ahmed travel and where did he go?[/I][/B] So, by viewing these 4 Possibilities Ahmed must traveled through Bus to either go to the City V or Z. [B][I]ii. Which mode of transport was used by the person who traveled to X city?[/I][/B] In every possibility Ali traveled through Aeroplane to reach the city X. |
Complete Solution of 11(a)
[B][I](i) How many stores does the distribution company serve?[/I][/B]
Total Number of stores = 3+15+26+20+16=[B][I]80[/I][/B] [B][I](ii) What is the most common distance of stores from the company's godown?[/I][/B] For this always see maximum frequency which is 26 in this table/case: So, The most common distance of stores from the company's godown is [B][I]21 to 30 kilometers[/I][/B] (because it has the maximum frequency; 26 stores). [B][I](iii) How many stores are 35 km or more from the godown?[/I][/B] From Table: There are [B][I]16 stores[/I][/B] which are [B][I]41 km or more from the godown[/I][/B], and [B][I]20 stores[/I][/B] which are between [B][I]31 to 40 km from the godown[/I][/B]. From the table we cannot say anything that how many of these 20 stores are 35 km or more from the godown. [B][I](iv) What percentage of stores are 31 km or more from the godown?[/I][/B] There are 20+16=36 stores which are 31 km or more from the godown. Hence, the percentage of these stores is given as, 36/Total no. of stores = 36/80 = 0.45 0.45 x 100% [B][I]45%[/I][/B] |
Complete Solution of 10(b)
[B][I]Data:[/I][/B]
15, 15, 16, 16, 16, 17, 17, 18, 19 [B][I]Solution:[/I][/B] The mean is defined as, the sum of the values divided by the number of values. The mean of the above data set is given as, =15+15+16+16+16+17+17+18+19/9 =149/9 =[B][I]16.556[/I][/B] [B][I]Median:[/I][/B] The middle value of an arranged data set is called median. Arranged data means writing the values in ascending order. The given values in ascending order are given as: 15, 15, 16, 16, 16, 17, 17, 18, 19 (already in ascending order) Hence, the median of the above data set is given as [U]15+15+16+16[/U]+16+[U]17+17+18+19[/U] Median = [B][I]16[/I][/B] [B][I]Mode:[/I][/B] The mode is the most repeated value in a data set. The most repeated value in the given data is 16. So, Mode = [B][I]16[/I][/B] [B][I]Range:[/I][/B] Range is the difference between the largest value and the smallest value. In the given data set the largest value is 19, and the smallest value is 15. Hence, Range = 19 − 15 = [B][I]4[/I][/B] |
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