#61




Q#6(a)
5 x 7 x 12 = 420 So after 415 seconds From the preliminary first 5, 7 and 12 ticking seconds together. 
#62




Q#6 (b)
One pipe filling the pool in 5 hours = 1.25 times If the second pipe is used with the same intensity of pressure for filling then in the given fives hours filling cspacity gets double So two pipes filling a pool with the same pressure in 5 hours = 2 x 1.25 (times) = 2.50 times Here the two pipes with the same capacity of filling the pool divided by 5 hours 5 hours /2.50 = 2 hours for the pipes with 1.25 times Slower pipe will take 5 hours for 1 time filling the pool as hour with slower capacity. Right I think ?? maths is difficult.
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#63




Quote:
Could you please explain your rationale? 
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