How far away a hubble telescope can see?

comparatively easy one

It was difficult than last EDS paper.

[QUOTE=Taimoor Gondal;913372]yes this question was wrong. instead of putting V or Z he put X again.
1 quetions ov percentage in mcqs portion was also wrong.
options were 20, 22.5, 25, 27.5.
but the correct option was 24 which was not present in options[/QUOTE]

i have to rearrange my maths skills to solve this question.

92.7 billion light years. thats the diameter of observable universe

Can anyone solve question 11 & 12?Please?

A) total number of stores 80
B) 21 to 30 km as 26 stores lie in this distance band
C) 16 stores at least because they are sure 41 kms away. We are not sure about how many stores are exactly farther than 35 km in 31-40 km range
D) 20+16=36/80*100: 45 percent stores are 31 or more km away.

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Weights of students in descending order ( highest to lowest) :
Ahmad
Ali
Shehbaz
Nasir
Akbar.

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Probability of AB blood group is number of people with AB/ total no.of people
=(125/1000)
=0.125
=12.5 percent

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[QUOTE=supergenius;918889]Weights of students in descending order ( highest to lowest) :
Ahmad
Ali
Shehbaz
Nasir
Akbar.

Sent from my SM-N910F using Tapatalk[/QUOTE]

Oh, an interesting story related to this question, after the paper, I asked a lady how she solved this question, she was saying by allocating the weight according to data given, she said that although, it consumed my 15 minutes but my answer was correct. And I was shocked her descending order of weight was absolutely correct.This is said to be a presence of mind.
About me,
(alhamdollilah, my majority of questions are also correct, though objective created problem for me)
And my folly, I did know the formula of range, but in hustle bustle I have not attempted.

So my answer is the same as of that lady?
Although I am sure about my answer but you know there is always another way to around to look at the problem at hand.

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[QUOTE=supergenius;919474]So my answer is the same as of that lady?
Although I am sure about my answer but you know there is always another way to around to look at the problem at hand.

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Yup, it is correct!:vic

Yeyyyyy!

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[QUOTE=supergenius;918889]Weights of students in descending order ( highest to lowest) :
Ahmad
Ali
Shehbaz
Nasir
Akbar.

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Its wrong. the descending order should be :
ahmad
ali
akbar
nasir
shehbaz

Solution:

ahmad > 3*ali
ali > 5*akbar
akbar > 0.5*nasir
nasir> 0.5*shehbaz

1) heaviest is Ahmad
2) lightest is shehbaz
3) shehbaz is lighter than all students
4) shehbaz is heavier than no one.
5) Descending order :
ahmad
ali
akbar
nasir
shehbaz :pipe

[QUOTE=ursula;919432]Oh, an interesting story related to this question, after the paper, I asked a lady how she solved this question, she was saying by allocating the weight according to data given, she said that although, it consumed my 15 minutes but my answer was correct. And I was shocked her descending order of weight was absolutely correct.This is said to be a presence of mind.
About me,
(alhamdollilah, my majority of questions are also correct, though objective created problem for me)
And my folly, I did know the formula of range, but in hustle bustle I have not attempted.[/QUOTE]

it took only 5-6 mints and done. :bow

@lonely, what makes you put inequality i.e. the greater than symbol, between variables?

Pit an equal sign and solve it.

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[QUOTE=supergenius;923352]@lonely, what makes you put inequality i.e. the greater than symbol, between variables?

Pit an equal sign and solve it.

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Yes it requires an equal mark. but its in order like
a>b>c>d>e .. no need to solve when its evident.
I would like to see what you did.

Ahmad= 3*ali
Ali= 5* akbar
Shehbaz= 4*akbar
Nasir= 2* akbar
Akbar= least

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[QUOTE=supergenius;923364]Ahmad= 3*ali
Ali= 5* akbar
Shehbaz= 4*akbar
Nasir= 2* akbar
Akbar= least

Sent from my SM-N910F using Tapatalk[/QUOTE]

:ninja::ninja::ninja:
its not shehbaz = 4*akbar
its akbar = 4*shehbaz

If you are taking "thrice as much as" as "Ahmad = 3*Ali" , then why are not doing the same to "half as much as" :ohmy:

No use studying
 

FPSC should not have given syllabus for this paper ...
more than 80% of paper was out of syllabus & QUESTIONS FROM STATS WERE SOOOO SOOOO SOOOO ANNOYING .. What of those who had never studied stats???? read the PRESCRIBED SYLLABUS and compare it with the paper given... NO USE STUDYING !!!!


..moreover, yes, calculator call was also given after candidates had already in their mind that " No calculators are allowed" ...FGS it was "ability" test as the name refers!
but those who went *out of the way* to bring calculators along , got profit.. RIP abiding by of rules..

Take it this way,
Akbar weighs half as much as nasir
Akbar is 1kg if nasir is 2kg.

Also nasir weighs half as much as shehbaz.
Nasir is 2kg if shehbaz is 4kg.

Therefore shehbaz weighs 4 times than akbar.

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But if you read half as much as twice, it is a different story. You can call me wrong, freedom of speech!

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[QUOTE=supergenius;923398]But if you read half as much as twice, it is a different story. You can call me wrong, freedom of speech!

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Then I will continue considering it because for me , its not 'half as less as'.
It can be moulded in both directions but lets just see in what way the examiner sees. Peace ! :laughing

@lonely

Ovations!
They say that there is always another way to look at the problem at hand. But a little google reveals that the jargon 'half as much as' in mathematics translates to both the 0.5 and 1.5. Lets see what the examiner choses.

Goodluck!

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[QUOTE=supergenius;923436]@lonely

Ovations!
They say that there is always another way to look at the problem at hand. But a little google reveals that the jargon 'half as much as' in mathematics translates to both the 0.5 and 1.5. Lets see what the examiner choses.

Goodluck!

Sent from my SM-N910F using Tapatalk[/QUOTE]

Exactly ! I also googled before posting. Both conditions were there. More inclined towards my side btw. :roll .. I thank you for giving my mind a little exercise. :D

Education
 

i m new here ....any body here ????????????

[QUOTE=Elizashy;927672]i m new here ....any body here ????????????[/QUOTE]
What's your query?

Couple of members asked you guys about the MCQs portion and all of you conveniently avoided. Seriously, how difficult was it to answer? Css me dua bht kam ati hai yd rkhna.

also mention the mcqs also bro

General Science and ability 2016 MCQ's
 

Hello all those who appeared in 2016.
Can you please share some of the MCQ's you remember from 2016? What sort of mathematical questions were there?

Can anyone post ans to question12 (b) part. It looks quite simple but i think it's technically wrong question.

[QUOTE=Noreturn;956876]Can anyone post ans to question12 (b) part. It looks quite simple but i think it's technically wrong question.[/QUOTE]

It's a simple question and there is no need to complicate it in your own head. The information is literally given and all you have to do is write 2 lines down D:

i) Ahmed went to V or Z by bus. Cannot be deciphered which, given the lack of information

ii) Ali went to X by air

It can be thought of as a trick question, given how easy it was and the heavy marks it held.

Part (i) cannot be deciphered with the given information.

solutions
 

can someone please solve these questions
and dont you think content and format of the paper changed abruptly in 2016

Book recommendation.
 

Those of you who thought they were able to do justice to this paper, kindly recommend a book.

[QUOTE=Klyptomaniac;962590]Those of you who thought they were able to do justice to this paper, kindly recommend a book.[/QUOTE]
You can learn better from youtube videos.

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[QUOTE=Nazish Hina;913455]The universe has a total distance of 17.7 billion light years. Some star is 17.3 billion light years away. If it is eliminated/extinguished today, when will we see it?

If 3P+q=14 and P+2Q=12
What is P?

*I'm not sure about the values :D[/QUOTE]

Theses values are valid
3P+q=14
P+2Q=12

=> P= (14 - q) /3 ______eq I
=> P= 12 - 2Q_________eq II
By subtracting, we get
3P+q=14
P+2Q=12
-----------------
2p+q-2Q = 2
Divinding by 2,we get

=>P+q/2-Q=1

=>P=Q-q/2
=>Q=P+q/2
=>q=2(Q-P)

Any aforementioned value can be find out by putting these in above equation I and II.





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[QUOTE=Mrkhansaab;956941]It's a simple question and there is no need to complicate it in your own head. The information is literally given and all you have to do is write 2 lines down D:

i) Ahmed went to V or Z by bus. Cannot be deciphered which, given the lack of information

ii) Ali went to X by air

It can be thought of as a trick question, given how easy it was and the heavy marks it held.

Part (i) cannot be deciphered with the given information.[/QUOTE]

it can deciphered without any doubt if you apply the rules of chronology.

The three boys, ali, akbar and nasir along with the mode of transport and destinations are in chronological order. Shahbaz who should have been placed on number two has been placed at number 5 just to ditch the candidates. If we place shahbaz on number two, everything will become clear.
thus Ahmad went to v by bus.
let me place all in chronological order
a. Ahmed went to v by bus
b. Shahbaz went to w by train
c. Ali went to x by air
d. Akbar went to y by car
e. Nasir went to z by boat

Salam! Can you please care to share your idea about an adequate length of an Answer--worth 5 marks-- to General Science questions?

[QUOTE=Farhan ak;983038]Salam! Can you please care to share your idea about an adequate length of an Answer--worth 5 marks-- to General Science questions?[/QUOTE]

One and a half page to 2 page of the answer sheet... With "effective" utilization of space... And diagram and flow chart etc

Complete Solution of 11(b)
 

Data:
1. Ahmad weighs thrice as much as Ali
[B][I]Ahmed=3(Ali)[/I][/B]

2. Ali weighs five times as much as Akbar
[B][I]Ali=5(Akbar)[/I][/B]

3. Akbar weighs half as much as Nasir
[B][I]Akbar=1/2(Nasir)[/I][/B]

4. Nasir weighs half as much as Shehbaz
[B][I]Nasir=1/2(Shahbaz)[/I][/B]

Solution:

Ahmed=3(Ali)
Ali=5(Akbar)
Akbar=1/2(Nasir)
Nasir=1/2(Shahbaz)

Let
Ahmed=a
Ali=b
Akbar=c
Nasir=d
Shahbaz=e

So,
a = 3b
b = 5c
c = 1/2(d) = 0.5d
d = 1/2(e) = 0.5e

Or,
a=3b
b=5c
d=2c
e=2d

As,
a=3b
and
b=5c

So,
a=3(b)=3(5c)=15c
a=15c

Similarly,
e=2d
and
d=2c

So,
e=2(d)=2(2c)=4c
e=4c

Now,
a=15c
b=5c
d=2c
e=4c

Arranging in descending order

a=15c
b=5c
e=4c
d=2c
c=c

In other words
Ahmed = 15(Akbar)
Ali = 5(Akbar)
Shahbaz = 4(Akbar)
Nasir = 2(Akbar)
Akbar = Akbar

So,
[B][I]i. Who is the heaviest in weight?[/I][/B]
Ahmed

[B][I]ii. Who is the lightest in weight?[/I][/B]
Akbar

[B][I]iii. Shahbez is lighter in weight than which of the two students?[/I][/B]
Ahmed and Ali

[B][I]iv. Shahbez is heavier in weight than which of the two students?[/I][/B]
Nasir and Akbar

[B][I]v. Show the descending order of weights of the two students?[/I][/B]
1. Ahmed
2. Ali
3. Shahbaz
4. Nasir
5. Akbar