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Noreturn Wednesday, August 03, 2016 06:21 AM

Can anyone post ans to question12 (b) part. It looks quite simple but i think it's technically wrong question.

Mrkhansaab Wednesday, August 03, 2016 12:48 PM

[QUOTE=Noreturn;956876]Can anyone post ans to question12 (b) part. It looks quite simple but i think it's technically wrong question.[/QUOTE]

It's a simple question and there is no need to complicate it in your own head. The information is literally given and all you have to do is write 2 lines down D:

i) Ahmed went to V or Z by bus. Cannot be deciphered which, given the lack of information

ii) Ali went to X by air

It can be thought of as a trick question, given how easy it was and the heavy marks it held.

Part (i) cannot be deciphered with the given information.

Huda Ahmed Thursday, August 18, 2016 05:33 AM

solutions
 
can someone please solve these questions
and dont you think content and format of the paper changed abruptly in 2016

Klyptomaniac Friday, August 26, 2016 02:23 PM

Book recommendation.
 
Those of you who thought they were able to do justice to this paper, kindly recommend a book.

supergenius Saturday, September 17, 2016 04:46 PM

[QUOTE=Klyptomaniac;962590]Those of you who thought they were able to do justice to this paper, kindly recommend a book.[/QUOTE]
You can learn better from youtube videos.

Sent from my SM-N910F using Tapatalk

Farhan Kaif Monday, September 19, 2016 09:57 AM

[QUOTE=Nazish Hina;913455]The universe has a total distance of 17.7 billion light years. Some star is 17.3 billion light years away. If it is eliminated/extinguished today, when will we see it?

If 3P+q=14 and P+2Q=12
What is P?

*I'm not sure about the values :D[/QUOTE]

Theses values are valid
3P+q=14
P+2Q=12

=> P= (14 - q) /3 ______eq I
=> P= 12 - 2Q_________eq II
By subtracting, we get
3P+q=14
P+2Q=12
-----------------
2p+q-2Q = 2
Divinding by 2,we get

=>P+q/2-Q=1

=>P=Q-q/2
=>Q=P+q/2
=>q=2(Q-P)

Any aforementioned value can be find out by putting these in above equation I and II.





Sent from my SM-E500H

abbas khan 119 Monday, September 19, 2016 06:02 PM

[QUOTE=Mrkhansaab;956941]It's a simple question and there is no need to complicate it in your own head. The information is literally given and all you have to do is write 2 lines down D:

i) Ahmed went to V or Z by bus. Cannot be deciphered which, given the lack of information

ii) Ali went to X by air

It can be thought of as a trick question, given how easy it was and the heavy marks it held.

Part (i) cannot be deciphered with the given information.[/QUOTE]

it can deciphered without any doubt if you apply the rules of chronology.

The three boys, ali, akbar and nasir along with the mode of transport and destinations are in chronological order. Shahbaz who should have been placed on number two has been placed at number 5 just to ditch the candidates. If we place shahbaz on number two, everything will become clear.
thus Ahmad went to v by bus.
let me place all in chronological order
a. Ahmed went to v by bus
b. Shahbaz went to w by train
c. Ali went to x by air
d. Akbar went to y by car
e. Nasir went to z by boat

Farhan ak Tuesday, November 01, 2016 04:15 PM

Salam! Can you please care to share your idea about an adequate length of an Answer--worth 5 marks-- to General Science questions?

hazelnut Tuesday, November 01, 2016 11:31 PM

[QUOTE=Farhan ak;983038]Salam! Can you please care to share your idea about an adequate length of an Answer--worth 5 marks-- to General Science questions?[/QUOTE]

One and a half page to 2 page of the answer sheet... With "effective" utilization of space... And diagram and flow chart etc

hammadtahir Saturday, January 28, 2017 01:10 AM

Complete Solution of 11(b)
 
Data:
1. Ahmad weighs thrice as much as Ali
[B][I]Ahmed=3(Ali)[/I][/B]

2. Ali weighs five times as much as Akbar
[B][I]Ali=5(Akbar)[/I][/B]

3. Akbar weighs half as much as Nasir
[B][I]Akbar=1/2(Nasir)[/I][/B]

4. Nasir weighs half as much as Shehbaz
[B][I]Nasir=1/2(Shahbaz)[/I][/B]

Solution:

Ahmed=3(Ali)
Ali=5(Akbar)
Akbar=1/2(Nasir)
Nasir=1/2(Shahbaz)

Let
Ahmed=a
Ali=b
Akbar=c
Nasir=d
Shahbaz=e

So,
a = 3b
b = 5c
c = 1/2(d) = 0.5d
d = 1/2(e) = 0.5e

Or,
a=3b
b=5c
d=2c
e=2d

As,
a=3b
and
b=5c

So,
a=3(b)=3(5c)=15c
a=15c

Similarly,
e=2d
and
d=2c

So,
e=2(d)=2(2c)=4c
e=4c

Now,
a=15c
b=5c
d=2c
e=4c

Arranging in descending order

a=15c
b=5c
e=4c
d=2c
c=c

In other words
Ahmed = 15(Akbar)
Ali = 5(Akbar)
Shahbaz = 4(Akbar)
Nasir = 2(Akbar)
Akbar = Akbar

So,
[B][I]i. Who is the heaviest in weight?[/I][/B]
Ahmed

[B][I]ii. Who is the lightest in weight?[/I][/B]
Akbar

[B][I]iii. Shahbez is lighter in weight than which of the two students?[/I][/B]
Ahmed and Ali

[B][I]iv. Shahbez is heavier in weight than which of the two students?[/I][/B]
Nasir and Akbar

[B][I]v. Show the descending order of weights of the two students?[/I][/B]
1. Ahmed
2. Ali
3. Shahbaz
4. Nasir
5. Akbar


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