Please help me i want to learn integration of math

[lllsagharlll]

What is integration and its basic concept. and what is cos sin and tan formulla

[Princess Royal]

Integration:-

The process of finding a function from its derived function is called integration. In short, it is the opposite of differentiation.

Integration of cos = sin + K
Integration of sin = -cos + K
There's no integration for tan.

'K' is an arbitrary constant.

[ravaila]

and here is all other common formula of integration.........................

http://www.cbu.edu/~wschrein/media/Calc2WS/Basic%20Integrals.pdf

in 1st forumla...........integration of 1 is always taken as "x" and constant "c"
has written wd all ans of integrating questions.............

in second formula ...........as "k " will b any constant i.e....2,3,4,....then u ll take its integration as "kx"....bcz k is constant it ll not change

in 3rd........when we have a power of "x" then we ll add 1 in its power and divided it by its power

in 4th ........when "x" is denomenator then we ll take its log

[osama24]

Saaghar mere dost,

Mai tujhe detail mai Integration explain karta hoon. But you have to pay full attention, read it again if there is some confusion, search the internet for basic answers (like cos, sin and tan) and even then if there is some confusion come back to me. The reason I am saying this is that I dont want you to be spoon fed, tuu khud thori effort kar ku k tera faida hai.

kher ji, integration is one of the most important and fundamental concepts of Calculus. As the name implies, integration means to integrate yeni k jama karna, akatha karna. Ab mai tujhe batata hoon k akatha karnay ka matlab kya hai..

lets start with the easiest and simplest example. aik function consider kar jiss mai y=x. This means that when x=1 y =1, x=2 y=2 and so on. Iss ko graph mai plot kar. As you can see, this is the graph of a line curved at 45 degrees (I hope you can understand this). Let the maximum value of x be 4. So our interval is from 0 to 4. It is written as [0,4].

Now is the best part, you can use integration to calculate the area under this line. HOW? Very simple.

As we know, the function on x axis is called x and the function on Y axis is called y. Since y is dependent upon the value of x so we write y as f(x). Using this, I will show you how to calculate the area under the curve and how it will be equal to the area calculated through the other formulae.

So, f(x)=x. Integrating both sides to get the area under the curve:

Area under the curve for the interval [0,4] is : Integration from 0 to 4 on x

As someone wrote in the post above, the integral of x is (x^2)/2. Hence for this interval, the value of this integral i.e. the area under the curve is: (4^2-0^2)/2=(16-0)/2=8. That is, the area under this curve is 8.

Now verifying this just to check whether the area calculated through integration is correct. If you plotted this correctly, you will see that it is a right angled triangle. The formula for calculation of area of Right angled triangle is: 1/2 * base* height. As you can see, the length of both the base and the height is same i.e. 4. So putting in the formula:

Area of Right Angle triangle is: 1/2 *4*4=8

So the answer is the same and hence using integration , we have calculated the area under the curve which is the same as calculated otherwise.

Using integration we can calculate areas under the curve in those cases when the area cant be calculated using simple formulas for example under the sinosoidal curve.

I have really tried to make it as simple for you as possible. I hope this was helpful and you have understood it.

Thanks,

Osama.