1. The product of the ages of A and B is 104. If thrice the age of B is less than A's age by 11 years. Find the B's age.
a. 10 years
b. 8 years
c. 12 years
d. 9 years


2. The present age of a mother is thrice the age of her son. If five years ago, the ratio of their ages is 1:4. Find the son's age after five years.

a. 15 years
b. 20 years
c. 12 years
d. 18 years

3. The ages of X and Y are in the ratio of 3:8 respectively and product of their ages is 384. Compute the ratio of their ages three years hence.

a. 3:5
b. 2:5
c. 3:7
d. 3:4


4. A is as much younger than B as he is older than C. If the sum of the ages of B and C is 40 years, what is the difference between B and C's age?

a. 3 years
b. 4 years
c. 5 years
d. Inadequate data.

5. The sum of the ages of a father and his son is 50. Ten years ago, the product of their ages was 56. Compute the present ages of son and father respectively.
a.
12 and 38
b.
38 and 12
c.
34 and 16
d.
16 and 34


6. At present the son's age is same as was his father's age at the time of his birth. If father's age is 48. Find the son's age after 4 years from now.
a. 30 years
b. 24 years
c. 28 years
d. Inadequate data


7. The age of a man is twice the sum of the ages of his two sons. Five years hence, his age will be 16 years more than the sum of the ages of his sons. What is the father's present age?

a. 42 years
b. 40 years
c. 45 years
d. Inadequate data


8. Given A is 12 years, B is two years younger than A ; C is 2 years elder than B.
Column A Column B
A+B B+C

a. The quantity in column A is greater.
b. The quantity in column B is greater.
c. Both the quantities are equal.
d. Relationship cannot be determined.


9. The sum of the present ages of a father and his son is 60 years. Six years ago, father's age was three times the age of the son. Determine the son's age after six years.

a. 24 years
b. 18 years
c. 12 years
d. 20 years


10. Four years ago, the ratio of ages of Purple and Blue was 2:3, respectively. If the sum of their present ages is 28. Compute the ratio of their ages four years hence.

a. 1:5
b. 2:5
c. 3:5
d. 4:5


11. The product of ages of son and mother is 720. and their ages are in the ratio 5:16. Find the son's age.

a. 15 years
b. 48 years
c. 22 years
d. 12 years

12. If the ratio of ages of Lee and Tee will be 5:9 after few years and their present ages are 12 and 24 respectively. Compute after how many years, their ages will be in the ratio 5:9.

a. 27 years
b. 3 years
c. 21 years
d. 13 years


13. The present ages of Tim and Lee are in the ratio of 5:6 respectively. Seven years hence, the ratio of their ages will be 6:7 respectively. What is Tim's present age?

a. 40 years
b. 32 years
c. 35 years
d. 34 years




Plz submit replies with equation/detailed solutions

Answer = (a) 15 years




Answer = (c) 3:7



Answer = (a) 12 and 38



Answer = (b) 3 years



Answer = (c) 35 years

Answer = (b) 8 years


(Errata : This sentence "If thrice the age of B is less than A's age by 11 years" should be read as "If thrice the age of B is greater than A's age by 11 years". Otherwise, answers we get is 4.33 and -8, none of which is correct.)


Answer = (b) 4 years


Answer = (c) 28 years

Answer = (a) 42 years


Answer = (c) Both the quantities are equal.

Answer = (a) 24 years


Answer = (d) 4:5

Answer = (a) 15 years

Ans of Q 2 is 20 years

present age thrice, 15 S and 45 M

before 5 years 1:4, 10 S and 40 M

After five years Son's age would be present age plus 5 so;

15+5=20 years.

Good