If n! is defined as the product of all positive integers from 1 to n, then:
1! = 1*1 = 1
2! = 1*2 = 2
3! = 1*2*3 = 6
4! = 1*2*3*4 = 24
5! = 1*2*3*4*5=120
Hence:
n! = 1*2*3*...*(n-2)*(n-1)*n
and so on.
In this way n! can also be expressed as n*(n-1)! .
Therefore, at n=1, using n! = n*(n-1)!
1! = 1*0!
Resultantly, 1 = 0!
Or:
n! = n*(n-1)!
n!/n = (n-1)!
If n=1 Then:
1!/1 = (1-1)!
1*1/1 = (0)!
1/1 = 0!
1=0!
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Last edited by Raz; Wednesday, August 04, 2010 at 10:52 PM.
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