Q#01
Solve the two sided inequality and show the solution on real line
7 < 1-2x ≤ 10

Solution:
=> 7 < 1-2x ≤ 10
multiply through out by (-)
=> -10 ≤ 2x-1 <-7
=> -9 ≤ 2x < -7
Divide through out by 2
=> -9/2 ≤ x < -7/2
Hence the resultant solution is semi close semi open interval [-9/2 , -7/2) on real line.

Q#03
Simplify, then apply the rules of limit to evaluate
lim x->3 x3(power3)-5x2(power2)+6x/x2(power2)-9

Solution:
lim x->3 {x3(power3)-5x2(power2)+6x/x2(power2)-9} --------> {c/0 form}
(Applying Lop-ital)
Differentiating both denominator and nominator w.r.t 'x'
=> lim x->3 {3x2(power2)-10x+6/2x}
Now applying limt
=> {3*(3^2)-10*3+6}/2*3
=> {27-30+6}/6
=> 3/6
=> 1/2 Ans

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