Quote:
Originally Posted by Raz
Suppose his average for 9 innings is X
After 10th inning his average becomes = x + 8
Formula for the calculation of average = Sum of All the items / Total Number of the items
We have effectively two items in this senario
1: 9 innings of X value
2: 10th inning of 100
Put these values in the above formula:
(X + 100)/2 = X+8
Solve this for X
you will arrive at X = 84, you know X is the average of first nine innings.
Hence his new average after 10th inning will be = 84+8=92
OR
=(X + 100) /2
= (84+100)/2
=92 Ans.
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But Brother, if his average prior to scoring 100 in the tenth match was 84, it meant that he would have scored 84*9=756 scores. And after scoring 100 in the tenth inning his total score would have become 756+100=856. And his new average out of 10 matches would be 856/10= 85.6. Which is not 8 more than the previous 84. So the calculations have led to the
erroneous result.
According to me his average of the nine innings was
20. After scoring 100 in the 10th inning his average would become [(20*9)+100]/10 =
28.
What do you say sir?
