Quote:
Originally Posted by Warraich
Answer is 38
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Solving method
Lets first even number= x
Then second consecutive even number= x+2
3rd consecutive even number= x+4
4th consecutive even number= x+6
5th (highest) consecutive even number= x+8.
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Now as per statement
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[x+(x+2)+(x+4)+(x+6)+(x+8)]/5= 38 // (dividing 5 because total number are 5)
x+(x+2)+(x+4)+(x+6)+(x+8)= 38*5
x+(x+2)+(x+4)+(x+6)+(x+8)= 190
5x+ 20=190
5x=170
x= 34
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So first number is 34
Hence highest number 34+8= 42
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Verification
Five consecutive numbers are; 34, 36, 38, 40, 42
Add them and take average 34+36+38+40+42= 190
Average=190/5
= 38
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The examiner asks "what is the highest number".The highest number among them is 42 not 38.
*u can't suppose x as even number, as x could be of any value i.e, 1,2,3,4 etc.
*u can't suppose x+2 as even number because if x=1, then number=3 and 3 is not an even number.