Quote:
Originally Posted by rabiaumar
yes 1/2
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Assuming that the coin is unbiased, and that landing on head and tail are exhaustive events.
So, P(first toss resulting in head) = 1/2
and P(second toss resulting in a tail)= 1/2 .
Since they are independent events, required probability (their product) is 1/4.
Another way to see it as:
Possible outcomes: HH, HT, TH and TT, each with equal probability. Hence, 1/4.
There is no other method to solve this question...