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Old Wednesday, September 07, 2016
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Quote:
Originally Posted by rabiaumar View Post
yes 1/2
Assuming that the coin is unbiased, and that landing on head and tail are exhaustive events.

So, P(first toss resulting in head) = 1/2
and P(second toss resulting in a tail)= 1/2 .

Since they are independent events, required probability (their product) is 1/4.

Another way to see it as:
Possible outcomes: HH, HT, TH and TT, each with equal probability. Hence, 1/4.

There is no other method to solve this question...
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