Quote:
Originally Posted by Ambber
The question didnt asked to find individual value of x,y Nd z and all three were not equal so division with 3 is not possible. It was asked find arithmetic average so the average of x, y z was 11. 11/3 is possible when question say that all three are equal which is not case here
I think merit would be around 70-75 because paper was tough and tricky as well
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I think I am right in this question. This was just to add these three equations and finding average of these three X,Y,Z by solving