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#11
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the question is about the speed of the wave not about the angular frequancy... the expression of wave speed is v = square root F/ u(mue) and mue = delta m/delta l so derive wave speed plz regards |
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ravaila (Thursday, September 22, 2011) |
#12
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sorry for so late reply.. I wasnt visiting forum very often.
So, my bad for going astray; I dont have the derivation with me now(did prepare physics while i was in village and now moved to city for some academy, so my physics derivation register is at home) but I will try to make it easier for you; Step 1: you can derive a wave eqaution in the form d2y/dx2= (1/v^2)* dy2/dt2 _________(1) I feel one may directly write it in exam as its a well known equation or derive it from simple y=Ym*Sin(kx -wt) in two steps; a- double diff y w.r.t x to get left hand side and double diff y w.r.t. "t" b- compare both side and put w/k=v; you will get the wave equation. The second equation is much difficult and lengthy to derive from newton secong law, get f=ma using some sine/cosine identities we express the forces in Y direction as related to X directionwith the help of a figure of the string; you will finally get a form as d2y/dx2= (u/F) d2y/dt2_________(2) compare 1 and 2 and get v=squareroot(F/u) I can upload details when i visit home if someone needs. For gradient, visit wikipedia page for definition and explanation in simple terms; It is an operator that turns a scalar function/field into a vector.(for easy understanding) theoretically; if we apply this operator on some function, it gives a vector that points towards max slope/change of the function in any direction. e.g if we apply this operator on a function f(x) which represents temperature in a room, the resultant will be a vector that points to max. temperature change in the room along any direction(as defined by function/field). Mathematics; Its diificult to make mathematics understandable in this writing format, search some examples of it online.
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very special 1 (Thursday, October 06, 2011) |
#13
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i think now this question is complete........ first portion ans how much marks you will give? yup now derivation is right........i understand it regards |
#14
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hmmm....
I can expect above average marks for an answer, but it wud be my first attempt this time , so idea about how marks are awarded here :s
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very special 1 (Sunday, October 16, 2011) |
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