kindly solve it with logic
 

The area of a 2-foot-wide walk around a garden that is 30 feet long and 20 feet wide is
A. 104 sq. ft.
B. 216 sq. ft.
C. 680 sq. ft.
D. 704 sq. ft.
E. 1416 sq. ft.

[QUOTE=muhammadalihamid;227040]The area of a 2-foot-wide walk around a garden that is 30 feet long and 20 feet wide is
A. 104 sq. ft.
B. 216 sq. ft.
C. 680 sq. ft.
D. 704 sq. ft.
E. 1416 sq. ft.[/QUOTE]
104 sq. ft

[QUOTE=muhammadalihamid;227040]The area of a 2-foot-wide walk around a garden that is 30 feet long and 20 feet wide is
A. 104 sq. ft.
B. 216 sq. ft.
C. 680 sq. ft.
D. 704 sq. ft.
E. 1416 sq. ft.[/QUOTE]
[B]Area of ground = 20*30 = 600 sq. ft.

Area including walk track = (20+4)* ( 30+4) = 24 * 34 = 816 sq. ft.

Area of track around the ground= 816 - 600 = 216 sq. ft.[/B]

It is the correct answer according to my perception.

2(2x34) + 2(2x20) = 136 + 80 = 216

[QUOTE=muhammadalihamid;227040]The area of a 2-foot-wide walk around a garden that is 30 feet long and 20 feet wide is
A. 104 sq. ft.
B. 216 sq. ft.
C. 680 sq. ft.
D. 704 sq. ft.
E. 1416 sq. ft.[/QUOTE]

216 sq ft...........

kindly tell why u add for while calculating area of track

my solution
 

length = 30 ft

width = 20 ft

walk around width = 2 ft

so, the walk around will increase both the length & width by 2+2=4 feet s.

so area of walk around the park = (34*24)-(30*20)

= 816 - 600

216 sq feet :laughing