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if f(x)=x^3; show that f(a,b,c)=a+b+c
This question is from second order divided difference.
it goes as follows we have f(x)=x^3 for first divided difference f(a,b) = {f(b)-f(a)}/(b-a) = {b^3-a^3}/(b-a) = a^2-ab+b^2 similarly f(b,c) = b^2-bc+c^2 now the second divided difference will be f(a,b,c) = {f(b,c)-f(a,b)}/(c-a) solving we get = a+b+c thus f(a,b,c) = a+b+c |
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LonelyEngineer (Tuesday, February 05, 2013) |
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