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question 14 of chap 8 of q k ghori book question 14 of chap 8 of q k ghori book

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Old Thursday, August 28, 2014
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Default question 14 of chap 8 of q k ghori book
answer given to this question in book is [2k[1/r - 1/R]]^1/2

while i am getting [2kR/{r[r+R]}]^1/2

any one any suggestions.... i think that answer in book is wrong :P
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Old Thursday, August 28, 2014
waqas izhar's Avatar
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a=vdv/dx=-k/(x^2)

implies

vdv=-kdx/(x^2)

integrate RHS from R to r

how did you solve it?
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Old Thursday, August 28, 2014
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Quote:
Originally Posted by waqas izhar View Post
a=vdv/dx=-k/(x^2)

implies

vdv=-kdx/(x^2)

integrate RHS from R to r

how did you solve it?
waqas bhai...
limits should be from r+R to r
because R is altitude {altitude is from surface of earth} and x is distance from center of earth as mentioned in question so when dropped from altitude R then x is actually R plus radius of earth r so x is r+R at altitude R

summing up

one limit of x at altitude R is = r+R
one limit of x at surface of earth is = r

:P
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