Friday, April 26, 2024
11:22 AM (GMT +5)

Go Back   CSS Forums > CSS Optional subjects > Group II > Physics
required help! required help!

Reply Share Thread: Submit Thread to Facebook Facebook     Submit Thread to Twitter Twitter     Submit Thread to Google+ Google+    
 
LinkBack Thread Tools Search this Thread
  #1  
Old Thursday, November 12, 2009
ravaila's Avatar
Senior Member
  
Join Date: Jan 2008
Location: city of miTTi kaTTA
Posts: 877
Thanks: 1,549
Thanked 798 Times in 436 Posts
ravaila is a glorious beacon of lightravaila is a glorious beacon of lightravaila is a glorious beacon of lightravaila is a glorious beacon of lightravaila is a glorious beacon of lightravaila is a glorious beacon of light
Default required help!
1--a clock keeps correct time with what speed should it moved relative to an observer so that it may appera to lose 4 minutes in 24 hours


2-- when two particals moved away from each other
what ll b their relative velocities...it ll doubled or remain equal?
__________________
Jo ALLAH karay c .. o sohna karay c
jab bhi kaam aaya mera PARVARIGAAR kaam aaya
Reply With Quote
  #2  
Old Tuesday, December 08, 2009
versatile.nadirmemon's Avatar
Junior Member
  
Join Date: Nov 2009
Posts: 2
Thanks: 0
Thanked 1 Time in 1 Post
versatile.nadirmemon is on a distinguished road
Default 2nd question
salamz dear iam nadir memon
i can give u answer of 2nd question....
actually there relative velocities become double....
Reply With Quote
The Following User Says Thank You to versatile.nadirmemon For This Useful Post:
ravaila (Saturday, December 12, 2009)
  #3  
Old Saturday, December 12, 2009
ravaila's Avatar
Senior Member
  
Join Date: Jan 2008
Location: city of miTTi kaTTA
Posts: 877
Thanks: 1,549
Thanked 798 Times in 436 Posts
ravaila is a glorious beacon of lightravaila is a glorious beacon of lightravaila is a glorious beacon of lightravaila is a glorious beacon of lightravaila is a glorious beacon of lightravaila is a glorious beacon of light
Default
ok thanks
i also got the and of my 1st question
__________________
Jo ALLAH karay c .. o sohna karay c
jab bhi kaam aaya mera PARVARIGAAR kaam aaya
Reply With Quote
  #4  
Old Saturday, December 12, 2009
Senior Member
  
Join Date: Aug 2009
Posts: 114
Thanks: 55
Thanked 36 Times in 23 Posts
aliz_khanz is on a distinguished road
Default
Help Please !!

Question :- calculate the distance of closest apprach for a head on collision between 5.30Mev alpha particle and nucleus of a copper atom?

Answer
The distance of closest
approach is given by

d= _______qQ_______
4*pie*e0*K base alpha

= ____________2*29*(1.60*10^-19C)^2_______
4*3.142*8.85*10^-12C^2/Nm^2*5.30MeV*1.60*10^-13J/MeV

= 1.4 * 10^ -6 aNSWER..........

NOW I AM CONFUSED HERE ABOUT ONE THING AND ITS EATING ME ALIVE.....FROM WHERE DID 1.60*10^-13J/MeV CAME ? I HAVE USED COLUMB'S LAW !
Reply With Quote
  #5  
Old Friday, June 25, 2010
mitariq's Avatar
Senior Member
  
Join Date: Oct 2009
Location: Classified
Posts: 127
Thanks: 5
Thanked 98 Times in 55 Posts
mitariq is on a distinguished road
Thumbs up
Quote:
Originally Posted by ravaila View Post
1--a clock keeps correct time with what speed should it moved relative to an observer so that it may appera to lose 4 minutes in 24 hours


Soln:
t'=t/sqrt(1-v2/c2)
this is the formula
the answer is 21*10^6m/s
Last edited by Andrew Dufresne; Saturday, June 26, 2010 at 02:24 AM.
Reply With Quote
  #6  
Old Saturday, June 26, 2010
Member
  
Join Date: Jun 2008
Location: karachi
Posts: 47
Thanks: 1
Thanked 7 Times in 7 Posts
celeron is on a distinguished road
Default @ravaila
ans of 2nd question is their velocity will be doubled
Reply With Quote
Reply

« Previous Thread | Next Thread »

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts
BB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Trackbacks are On
Pingbacks are On
Refbacks are On

Similar Threads
Thread Thread Starter Forum Replies Last Post
Mobile codes nice051 Computers and Technology 4 Monday, December 10, 2007 09:56 AM

CSS Forum - Privacy Statement - Terms of Service - Top

CSS Forum on Facebook Follow CSS Forum on Twitter

Disclaimer: All messages made available as part of this discussion group (including any bulletin boards and chat rooms) and any opinions, advice, statements or other information contained in any messages posted or transmitted by any third party are the responsibility of the author of that message and not of CSSForum.com.pk (unless CSSForum.com.pk is specifically identified as the author of the message). The fact that a particular message is posted on or transmitted using this web site does not mean that CSSForum has endorsed that message in any way or verified the accuracy, completeness or usefulness of any message. We encourage visitors to the forum to report any objectionable message in site feedback. This forum is not monitored 24/7.

Sponsors: ArgusVision   vBulletin, Copyright ©2000 - 2024, Jelsoft Enterprises Ltd.