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  #1041  
Old Wednesday, September 07, 2016
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Quote:
Originally Posted by Aqeel Zafar View Post
Assuming that the coin is unbiased, and that landing on head and tail are exhaustive events.

So, P(first toss resulting in head) = 1/2
and P(second toss resulting in a tail)= 1/2 .

Since they are independent events, required probability (their product) is 1/4.

Another way to see it as:
Possible outcomes: HH, HT, TH and TT, each with equal probability. Hence, 1/4.

There is no other method to solve this question...
Brother this is simple question why you are confusing your self.

Probability of head in two attempts is 50 50.

see first you tossed coin probability of head is 1/2.

Again you tossed coin probability of head is 1/2.

Now simplify the equation by adding 1/2+1/2= 2/4 => 1/2.

Two attempts was just to confuse the question
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  #1042  
Old Wednesday, September 07, 2016
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test wasnt dat easy... expecting 70+ in both test...

If tukkas went well might well score 80 plus
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  #1043  
Old Wednesday, September 07, 2016
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A's age thirty years ago was 1/6 of the present age. What is the present age?
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  #1044  
Old Wednesday, September 07, 2016
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5 years
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  #1045  
Old Wednesday, September 07, 2016
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Quote:
Originally Posted by mohsinali303 View Post
Brother this is simple question why you are confusing your self.

Probability of head in two attempts is 50 50.

see first you tossed coin probability of head is 1/2.

Again you tossed coin probability of head is 1/2.

Now simplify the equation by adding 1/2+1/2= 2/4 => 1/2.

Two attempts was just to confuse the question
Brother with no offence, if you add 1/2+1/2=2/2 which is equal to 1. if in the question or was written instead of "and" than we could use addition formula but because of word and we have to multiply both the probabilities.
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  #1046  
Old Wednesday, September 07, 2016
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Quote:
Originally Posted by Aqeel Zafar View Post
Assuming that the coin is unbiased, and that landing on head and tail are exhaustive events.

So, P(first toss resulting in head) = 1/2
and P(second toss resulting in a tail)= 1/2 .

Since they are independent events, required probability (their product) is 1/4.

Another way to see it as:
Possible outcomes: HH, HT, TH and TT, each with equal probability. Hence, 1/4.

There is no other method to solve this question...
Here we simply count samples which have only ONE head and that is 2 times(HT, TH). now find its probability. P=K/N= 2/4, N is total no. of samples
REf; Statistics Part II, Chap 12.
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  #1047  
Old Wednesday, September 07, 2016
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Quote:
Originally Posted by mohsinali303 View Post
Brother this is simple question why you are confusing your self.

Probability of head in two attempts is 50 50.

see first you tossed coin probability of head is 1/2.

Again you tossed coin probability of head is 1/2.

Now simplify the equation by adding 1/2+1/2= 2/4 => 1/2.

Two attempts was just to confuse the question
Bhai What are you doing with basic math operations.
1/2+1/2=????? it is 1 not 2/4=1/2
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  #1048  
Old Wednesday, September 07, 2016
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CURRENT AGE IS 36 BECAUSE 1/6 OF 36 IS 6, AND 30 years ago his age was 6
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  #1049  
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why Two blanket are more warmer than single one?
I answered due to compression of air
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  #1050  
Old Wednesday, September 07, 2016
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Quote:
Originally Posted by Jsajid View Post
Here we simply count samples which have only ONE head and that is 2 times(HT, TH). now find its probability. P=K/N= 2/4, N is total no. of samples
Ref; Statistics Part II, Chap 12.
This is an agreeable solution with proper logic.
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