He is Right dear at that time ABL did not allowed the honers degree holders to participate in the interview and on the interview latter if any BBA or other got this by fault he/she kindly did not come for interview..

but i do not know what is the policy this time???
any one need to call ABL and ask for the policy..

HOW?


Please Explain Calculation..

let base be 'x' and altitude be 'y' then the area will be 'xy'

given;
base increased as, x + 0.3 x = 1.3 x
altitude decreased as, y - 0.2 y = 0.8 y
according to given condition, the area will be 1.3 x * 0.8 y = 1.04 xy

1.04 xy - xy = 0.04 xy (which 4%)

that's why area increased by 4%

round of degree is 360 so for i hour it will be 360 n for 2 hours it will be 360+360=720 now for 12 minutes add 720+12=732.
ans is 732.

none of these

Answer: A. 66

Solution: A clock has 360 degrees from 12 noon to 12 midnight. In one hour there are 360 degrees divided by 12 hours equals to 30 degrees for one hour, for 12 Minutes, 12/20= .20.

For 2 Hours and 12 minutes: you will multiply 2.20 X 30 = 66.

if you notice in question, they asked for "the hour hand of a clock" only.

__________________
Regards,
~ Riz ~

.

right ans is 66

__________________
.~.The greatest mistake one can make is to be afraid of not making them.~.

A train running between two towns arrives at its destination 10 minutes late when it
goes 40 miles per hour and 16 minutes late when it goes 30 miles per hour. The
distance between the two towns is
A. 720 miles
B. 12 miles
C. 8-6/7 miles
D. 12-7/7 miles
E. None of these

__________________
.~.The greatest mistake one can make is to be afraid of not making them.~.

The answer is B,

Solution: This will be done by setting up two equations from
distance = Speed x Time travel

For 1st case: d = 40 x (t+10/60)-------- Eq. 1
this will become d= 40t + 400/60

For 2nd case: d= 30 x (t + 16/60)---------Eq. 2
this will become d= 30t + 480/60

Note: We take t+10/60 because in first case train reached 10minutes late and same for 2nd case

Now as both equation's L.H.S is same i.e d, therefore compare both equations by which we got

40t + 400/60 = 30t + 480/60
Now, solve this equation for t, like

40t-30t = 480/60 - 400/60
10t = 80/60
10t = 8/6
t= 8/6*10
t=8/60 or 8 Minutes (as we know that the hours is equal to 60 minutes, therefore 8/60 is equal to 8 Minutes)

Now put this value in either of equation

d= 40 x (t+10/60)

t= 8/60

d= 40 x (8/60 + 10/60)
d= 12 miles

__________________
Regards,
~ Riz ~

Age problems


The purpose of this lesson is to show you how to solve Age problems.

Problem 1


Kevin is 4 years older than Margaret.
Next year Kevin will be 2 times as old as Margaret.
How old is Kevin?

Solution
Denote as Kevin's present age.
Then Margret's present age is .

Next year Kevin will be years old, and Margaret will be years old.

Since next year Kevin will be 2 times as old as Margaret, you can write the equation
.

Solve this equation by simplifying it, step by step:

(after brackets opening at the right side)
(after moving variable terms to the right and constant terms to the left)
(after combining like terms)

Thus, you got that Kevin's present age is years.

Check.
If Kevin's present age is 7 years, then Margaret is years old now.
Next year Margaret will be 4 years old, while Kevin will be 8 years old, which means that next year Kevin will be 2 times as old as Margaret.
The solution is correct.

Answer. Kevin is 7 years old now.

Problem 2


Ann is 2 years older than Betty.
Last year Ann was 2 times as old as Betty.
How old is Ann?

Solution
Denote as Ann's present age.
Then Betty's present age is .

Last year Ann was years old, and Betty was years old.

Since last year Ann was 2 times as old as Betty, you can write the equation
.

Solve this equation by simplifying it, step by step:

(after brackets opening at the right side)
(after moving variable terms to the right and constant terms to the left)
(after combining like terms)

Thus, you got that Ann's present age is years.

Check.
If Ann's present age is 5 years, then Betty is years old now.
Last year Ann was 4 years old, while Betty was 2 years old, which means that last year Ann was 2 times as old as Betty.
The solution is correct.

Answer. Ann is 5 years old now.

Problem 3


Susan is 3 years older than Tom. Two years ago Susan was twice as old as Tom.
Find their present ages.

Solution
Denote as Tom's age 2 years ago.
Then Susan's age was 2 years ago.

Tom's age is at present.
Susan's age is at present.

Since Susan is 3 years older than Tom, you can write the equation
.

Solve this equation by simplifying it, step by step:
(after combining like terms at the right side)
(after moving variable terms to the right and constant terms to the left)
(after combining like terms)

Thus, you got that Tom was years old two years ago.
Hence, Susan was years old at that time.
At present, Tom is years old, and Susan is years old.

Answer. At present, Tom is 5 years old, and Susan is 8 years old.

Problem 4


Jerry is 7 years older than Jennifer. In three years Jerry will be twice as old as Jennifer.
Find their present ages.

Solution
Denote as Jennifer's present age.
Then Jerry's present age is .

In three years Jennifer's age will be , while Jerry's age in three years will be .
Since in two years Jerry will be twice as old as Jennifer, you can write the equation
.

Solve this equation by simplifying it, step by step:
(after brackets opening at the right side)
(after moving variable terms to the right and constant terms to the left)
(after combining like terms)

Thus, you got that Jerry's present age is years.
Hence, Jennifer's present age is years.

In three years, Jerry will be years old, while Jennifer will be years old.

Answer. At present, Jerry is 4 years old, and Jennifer is 11 years old.

Problem 5


A man has a daughter and a son.
The son is three years older than the daughter.
In one year the man will be six time as old as the daughter is now.
In ten years the man will be fourteen years older than the combined ages of his children at that time.
What is the man's present age?

Solution
Denote as the daughter's present age.
Then the son's present age is .

Since in one year the man will be six time as old as the daughter is now, the man's present age is .
In ten years the man's age will be , while the daughter's age will be and the son's age will be .

Since in ten years the man will be fourteen years older than the combined ages of his children at that time, you can write an equation
.

Solve this equation by simplifying it, step by step:
(after combining like terms at the right side)
(after moving variable terms to the right and constant terms to the left)
(after combining like terms)
.

Thus, you got that the daughter's present age is years.
Hence, the son's present age is years, and the man's present age is .

Answer. At present, the man is 41 years old.